A die means a standard cube whose faces are numbered 1, ..., 6 and each has equal probability of being rolled. A green die and a red die are rolled simultaneously, with equal probability for each of the 36 possible outcomes. Describe the sample space. Then find the probability that: a. the sum is 7;
b the sum is 11;
thesumis7or11;
thesumisneither7nor11;
b. the same value occurs on each die;
c. the value on the green die is greater than 5;
d. the value on each die is less than 6;
e. the sum is even.
red/green | 1 | 2 | 3 | 4 | 5 | 6 |
1 | 11 | 21 | 31 | 41 | 51 | 61 |
2 | 12 | 22 | 32 | 42 | 52 | 62 |
3 | 13 | 23 | 33 | 43 | 53 | 63 |
4 | 14 | 24 | 34 | 44 | 54 | 64 |
5 | 15 | 25 | 35 | 45 | 55 | 65 |
6 | 16 | 26 | 36 | 46 | 56 | 66 |
total possible outcomes =36
a) sum is 7
possible outcomes are(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)
so,P(sum is 7)=6/36 = 1/6
b) sum is 11
possible outcomes are(5,6)(6,5)
so ,P(sum is 11) = 2/36
c) P(sum is 7 or 11)=P(sum is 7)+P(sum is 11) = 6/36+2/36 = 8/36 = 2/9
d)P( sum is neither 7 or nor 11 ) = 1-P(sum is 7 or 11) = 1-8/36
= 28/36 = 7/9
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b. the same value occurs on each die;
possible outcomes are (11)(22)(33)(44)(55)(66)
so, probability = 6/36 = 1/6
c) value on green die will be 6 and red die can take any
value
possible outcomes are = (1,6)(2,6)(3,6)(4,6)(5,6)(6,6)
P(value on green die is greater than 5)=6/36 = 1/36
d)
possible outcomes are
11 | 21 | 31 | 41 | 51 |
12 | 22 | 32 | 42 | 52 |
13 | 23 | 33 | 43 | 53 |
14 | 24 | 34 | 44 | 54 |
15 | 25 | 35 | 45 | 55 |
so, P(value on each die is less than 6) = 25/36
e)
possible outcomes are
11 | 31 | 51 | |||
22 | 42 | 62 | |||
13 | 33 | 53 | |||
24 | 44 | 64 | |||
15 | 35 | 55 | |||
26 | 46 | 66 |
P(sum is even) = 18/36 = 1/2
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