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QUESTION 4 1 points Save Answer By how much would the temperature of 9.13 g of pure water increase when 0.910 kJ of heat is a
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Heat m Cp AT O.91o X 103J= 9.13g x 4.18T/g 9) xAT O-910 x103 T = 38.1634 x OT AT= 0.910 x103 J 38-1634 J/c AT = 23.84c AT= 23

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