Will rate! Guppose the time between buses at a particular stop is a positively skewed random...
Suppose the time between buses at a particular stop is a positively skewed random variable with an average of 59 minutes and standard deviation of 6 minutes. Suppose the time between buses at this stop is measured for a randomly selected week, resulting in a random sample of n = 38 times. The average of this sample, X , is a random variable that comes from a specific probability distribution. (a)Which of the following is true about the distribution of...
Run times at a local marathon are known to follow a left-skewed distribution with a mean of 252 minutes and a standard deviation of 116 minutes. If we select a random sample of 59 people, what is the probability that the average run time of this sample will be between 247.469 minutes and 259.551 minutes? Select one: a. 0.3094 b. 0.6915 c. 0.3821 d. 0.0415 e. We cannot answer the question with the information given.
The EMS response time from a notification to the arrival of a crash site in an urban area has a mean of 6.8 minutes and a standard deviation of approximately 3 minutes. The population distribution is skewed right (positively skewed). a) If we looked into a random sample of 34 crashes in an urban area, then would it be reasonable to say that the sampling distribution of a sample mean, , will be approximately normal? Answer either yes or no....
Question number-2: Run times at a local marathon are known to follow a left-skewed distribution with a mean of 244 minutes and a standard deviation of 109 minutes. If we select a random sample of 57 people, what is the probability that the average run time of this sample will be between 226.675 minutes and 269.987 minutes?
Runtimes at a local marathon are known to follow a left-skewed distribution with a mean of 256 minutes and a standard deviation of 66 minutes if we select a random sample of 57 people, what is the probability that the average run time of this sample will be between 238 516 minutes and 261 245 minutes? Select one a 0.1361 b0 7257 c. We cannot answer the question with the information given Od 0.7030
The shape of the distribution of the time required to get an ail change at a 10-minute oil-change facility is skewed right. However, records indicate that the mean time is 11.3 minutes, and the standard deviation is 3.1 minutes. Complete parts (a) through (c). (a) To compute probabilities regarding the sample mean using the normal model, what size sample would be required? A. The normal model cannot be used if the shape of the distribution is skewed right. B. Any sample size could...
uestion (1) (30 Marks A) 5 Marks) The time required to build a computer is normally distributed with a mean of 50 minutes and a standard deviation of 10 minutes. What is the probability thata computer is assembled in a time between 45 and 60 minutes? B) (5 Marks) t was noted that the amount of oil in each "32-ounce" bottle is actually a normally distributed random variable, with a mean of 32.2 ounces and a standard deviation of 0.3...
nswer the following TWO questions uestion (1) (30 Marks A) (5 Marks) The time required to build a computer is normally distributed with a mean of 50 minutes and a standard deviation of 10 minutes. What is the probability that a computer is assembled in a time between 45 and 60 minutes? B) (5 Marks) It was noted that the amount of oil in each "32-ounce" bottle is actually a normally distributed random variable, with a mean of 32.2 ounces...
LUULIS spend scuoying per week have a distribution skewed to the right with a mean of 8.6 hours and a standard deviation of 28 houm Find the probability that the mean time spent studying per week for a random sample of 49 college students would be between 8.2 and 8.9 hours. Round your answer to two decimal places. Attach File Browse My Computer Browse Content Collection Browse Dropbox QUESTION 4 Let x denote the time it takes to run a...
The arrival time t(in minutes) of a bus at a bus stop is uniformly distributed between 10:00 A.M. and 10:03 A.M. (a) Find the probability density function for the random variable t. (Let t-0 represent 10:00 A.M.) (b) Find the mean and standard deviation of the the arrival times. (Round your standard deviation to three decimal places.) (с) what is the probability that you will miss the bus if you amve at the bus stop at 10:02 A M ? Round your answer...