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#1000K? 12. The equilibrium constant,ke, for the reaction H() + 12(g) 2 HI(g) 13542 0 40 mol sample of HI was introduced into

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2HI(g 12) Equilibrium: H,(g)I(g) ; K 33 For reverse reaction 1 = 0.0303 33 2HI(g H2 (g) (g) ;K = 0.40 mol Concentrati on of H

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