Question

At 6 oC the equilibrium constant for the reaction:

2 HI(g) revrxnarrow.gif H2(g) + I2(g)

is KP = 2.66e-11. If the initial pressure of HI is 0.00837 atm, what are the equilibrium partial pressures of HI, H2, and I2?At 6 °C the equilibrium constant for the reaction: 2 HI(g) = H2(g) + 12(g) is Kp = 2.66e-11. If the initial pressure of HI is

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Answer #1

HOU Z H₂ (g) + Iz (g) Ke=2.668 10-11 / At 6°C) Attro Po = 0.00837 - atm - At tatą Po -2p) p p . 710 (Approssimation) - as Kp

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