Question

(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) +...

(1).

The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K.

2HI(g) =H2(g) + I2(g)

If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is  atm.

(2).
Consider the following reaction:

PCl5(g) =PCl3(g) + Cl2(g)

If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at equilibrium in a 14.9 L container at 709 K, the value of the equilibrium constant, Kp, is .

(3). The equilibrium constant, Kp , for the following reaction is 0.215 at 673 K.  

NH4I(s) =NH3(g) + HI(g)

If an equilibrium mixture of the three compounds in a 5.88 L container at 673 K contains 2.44 mol of NH4I(s) and 0.217 mol of NH3(g), the partial pressure of HI(g) is  atm.

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