The following reaction has equilibrium constant of Kp = 11.5 atm at 300 oC: PCl5(g) PCl3...
The following reaction has equilibrium constant of Kp = 11.5 atm at 300 oC: PCl5(g) PCl3 (g) + Cl2 (g). A flask was charged with pure PCl5 (g) and allowed to achieve the equilibrium, at which partial pressure of PCl5 (g) was 1.50 atm. Find (a) total pressure at equilibrium (b) partial pressures of PCl3 (g) and Cl2(g), (c) initial pressure of PCl5.
Homework Answers
Add Answer to:
The following reaction has equilibrium constant of Kp = 11.5 atm
at 300 oC: PCl5(g) PCl3...
The equilibrium constant (Kp) for the interconversion of PCl5 and PCl3 is 0.0121 at certain temperature....
The equilibrium constant (Kp) for the interconversion of PCl5 and PCl3 is 0.0121 at certain temperature. A vessel is charged with PCl5 giving an initial pressure of 0.123 atm. PCl5 (g) ⥦ PCl3 (g) + Cl2 (g) a) Calculate equilibrium partial pressure of PCl3 b) Calculate total pressure at equilibrium
For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5. PCl5(g) PCl3(g) + Cl2(g) Suppose that 2.21...
For the following reaction at 600. K, the equilibrium constant,
Kp, is 11.5.
PCl5(g)
PCl3(g) + Cl2(g)
Suppose that 2.210 g of PCl5 is placed in an
evacuated 535 mL bulb, which is then heated to 600. K.
(a)
What would be the pressure of PCl5 if it did not
dissociate?
(b)
What is the partial pressure of PCl5 at
equilibrium?
(c)
What is the total pressure in the bulb at equilibrium?
(d)
What is the degree of dissociation of...
1. The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <---->...
1. The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <----> PCl3(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PCl5(g) is introduced into an evacuated flask at a pressure of 1.00 atm at 500 K. PPCl5 = atm PPCl3 = atm PCl2 = atm 2. The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K: NH4I(s) <----> NH3(g) + HI(g) Calculate the equilibrium partial pressure of HI when...
The equilibrium constant Kp for the reaction PCl5(g) <---> PCl3(g) + Cl2(g) is 1.15 at 25...
The equilibrium constant Kp for the reaction PCl5(g) <---> PCl3(g) + Cl2(g) is 1.15 at 25 degrees Celsius. The reaction starts with a mixture of 0.177 atm PCl5, 0.223 atm PCl3, and 0.111 atm Cl2. When this mixture comes to equilibrium at 25 degrees Celsius, what are the equilibrium pressures of each component?
At 500 K the reaction PCl5(g) <----> PCl3(g) + Cl2(g) has Kp = 0.497. In an...
At 500 K the reaction PCl5(g) <----> PCl3(g) + Cl2(g) has Kp = 0.497. In an equilibrium mixture at 500 K, the partial pressure of PCl5 is 0.860 atm and that of PCl3 is 0.350 atm. What is the partial pressure of Cl2 in the equilibrium mixture?
What are the equilibrium partial pressures of PCl3 , Cl2, and PCl5, respectively? Express your answers...
What are the equilibrium partial pressures of PCl3, Cl2, and PCl5, respectively?Express your answers numerically in atmospheres with three digits after the decimal point, separated by commas.An Equilibrium Study: Phosphorus Trichloride/Phosphorus Pentachloride EquilibriumFor the exothermic reactionPCl3(g)+Cl2(g)→PCl5(g)Kp = 0.180 at a certain temperature.A flask is charged with 0.500 atm PCl3 , 0.500 atm Cl2, and 0.300atm PCl5 at this temperature.
The equilibrium partial pressures for the reaction Cl2 (g) + PCl3 (g) ↔ PCl5 (g) at...
The equilibrium partial pressures for the reaction Cl2 (g) + PCl3 (g) ↔ PCl5 (g) at 300 K are PCl2 = 0.75 atm, PPCl3 = 0.45 atm, and PPCl5 = 0.73 atm. The value of Kp is __________. A. 0.15 B. 0.048 C. 4.7 D. 2.16
The equilibrium PCl5(g) ⇄ PCl3(g) + Cl2(g) is established at 250oC. At equilibrium the partial pressures...
The equilibrium PCl5(g) ⇄ PCl3(g) + Cl2(g) is established at 250oC. At equilibrium the partial pressures of the components are 0.020 Atm (PCl5), 1.28 Atm (PCl3), and 1.28 Atm (Cl2). If the partial pressure of Cl2 is suddenly increased to 2.15 Atm, what is the partial pressure of PCl5 after equilibrium has been reestablished?
At 2935 oC the equilibrium constant for the reaction: 2 BrCl(g) Br2(g) + Cl2(g) is KP...
At 2935 oC the equilibrium constant for the reaction: 2 BrCl(g) Br2(g) + Cl2(g) is KP = 0.732. If the initial pressure of BrCl is 0.00845 atm, what are the equilibrium partial pressures of BrCl, Br2, and Cl2? p(BrCl) = p(Br2) = p(Cl2) =
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) +...
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) + I2(g) If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is atm. (2). Consider the following reaction: PCl5(g) =PCl3(g) + Cl2(g) If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at...
For the following reaction at 600. K, the equilibrium constant,
Kp, is 11.5.
PCl5(g)
PCl3(g) + Cl2(g)
Suppose that 2.210 g of PCl5 is placed in an
evacuated 535 mL bulb, which is then heated to 600. K.
(a)
What would be the pressure of PCl5 if it did not
dissociate?
(b)
What is the partial pressure of PCl5 at
equilibrium?
(c)
What is the total pressure in the bulb at equilibrium?
(d)
What is the degree of dissociation of...
Most questions answered within 3 hours.
-
Protons in cosmic rays have been observed with kinetic energies
as large as 1.0×1020eV.
How fast...
asked 38 minutes ago -
How do you explain that it is not fair for teachers to verbally
abuse you over...
asked 37 minutes ago -
Ang Electronics, Inc., has developed a new HD DVD. If the HD DVD
is successful, the...
asked 1 hour ago -
which of these substances cannot behave as a lewis base in an aq
solution
a- Co...
asked 1 hour ago -
Below are some of Toyota’s (an automotive manufacturer) costs to
manufacture a car: I. Depreciation of...
asked 1 hour ago -
A random sample of 40 cups of coffee from a vending machine had
a sample mean...
asked 1 hour ago -
The mercury in a fish sample is determined to be 1.80, 1.58 and
1.64 ppm. Calculate...
asked 1 hour ago -
Suppose a photon is equally likely to be found anywhere in an
interval of 28.5 cm...
asked 1 hour ago -
Suppose the following is a divide-and-conquer algorithm for some
problem.
"Make the input of size n...
asked 2 hours ago -
Calculate the pH of the resulting solution if 15.0 mL of 0.150 M
HCl(aq) is added...
asked 2 hours ago -
How many moles of sulphur hexaflouride are present in 3.64 x 10^21
molecules of this compound?
asked 2 hours ago -
155 grams of ice at -10.0 degrees celsius is added to 1.17 kg of
water at...
asked 2 hours ago