At 2935 oC the equilibrium constant for the reaction: 2 BrCl(g) Br2(g) + Cl2(g) is KP...

Question

Question

At 2935 oC the equilibrium constant for the reaction:

2 BrCl(g) Br2(g) + Cl2(g)

is KP = 0.732. If the initial pressure of BrCl is 0.00845 atm, what are the equilibrium partial pressures of BrCl, Br2, and Cl2?

p(BrCl) =

p(Br2) =

p(Cl2) =

Answer 1

Answer #1

Answer 2

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