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155 grams of ice at -10.0 degrees celsius is added to 1.17 kg of water at...

155 grams of ice at -10.0 degrees celsius is added to 1.17 kg of water at 70.0 degrees celsius and mixed together in thermal isolation until they come to equilibrium. The specific heat of ice is 2010 J/kgC. The specific heat of water is 4186 J/kgC. The latent heat of fusion for water is 3.34x10^5 J/kg. The latent of vaporization for water is 2.26x10^6 J/kg. What is the final equilibrium. The answer is 51.9 celsius. I just need the steps on how to do it.

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