Question

A 200 g piece of ice at 0 degrees Celsius is place in 500 g of water at 20 degrees Celsius. The system is in a container of negligible heat capacity and insulated from its surroundings. a) What is the final equilibrium temperature of the system? b) How much of the ice melts? The latent heat of fusion for water is (333.5 KI/kg). The specific heat of water is 4.18 KI/kg K Useful equations: Q = mlf and Q = mcAT

Answer 1

mans of ice mass of water miz zooga 0.2 kg mw- 500g= 0.5kg is hear Arrume m kg of ice were melted : Heat required for transition this - m x 333.58103 J to oc, then comes at zoe If heat the water expelled H₂ = mw x 4.188103 x (20-0) = 0.58 4.188103 x20 $41.88 103 5 First Law of thermodynanies, .: From Hi= H₂ = mx 333.5 x103 = 41.88103

si me 0.125 g. 2 125 gm ice will | 125 gm melt. not helting therefore ce mixture will is the As the we can remain whole ice say that at ore. temp = oe a) Final equilibrium ice will helt. 6) 125 gm