The equilibrium constant, Kc, for the following
reaction is 55.6 at 698 K:
H2(g) +
I2(g)
---------->2HI(g)
1) Calculate the equilibrium concentrations of reactants and
product when 0.309 moles of
H2 and 0.309 moles of
I2 are introduced into a 1.00 L vessel
at 698 K.
[H2] | = | M? |
[I2] | = | M? |
[HI] | = | M? |
2.The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K:
An equilibrium mixture of the three gases in a 1.00 L flask at
500 K contains 0.210 M
PCl5,
5.02×10-2 M
PCl3 and
5.02×10-2 M
Cl2. What will be the concentrations of
the three gases once equilibrium has been reestablished, if
4.12×10-2 mol of
PCl3(g) is added to the
flask?
[PCl5] | = | M? |
[PCl3] | = | M? |
[Cl2] | = | M? |
3.The equilibrium constant, K, for the following reaction is 5.01×10-2 at 538 K:
An equilibrium mixture of the three gases in a
16.4 L container at 538 K
contains 0.153 M PCl5,
8.74×10-2 M
PCl3 and
8.74×10-2 M
Cl2. What will be the concentrations of
the three gases once equilibrium has been reestablished, if the
equilibrium mixture is compressed at constant temperature to a
volume of 7.71 L?
[PCl5] | = | M? |
[PCl3] | = | M? |
[Cl2] | = | M? |
4. The equilibrium constant, Kp, for the following
reaction is 55.6 at 698 K:
H2(g) +
I2(g)
----------->2HI(g)
If ΔH for this reaction is -10.4 kJ, what is the
value of Kp at 623 K?
Kp = ?
1) H2(g) + I2(g) ----------> 2HI(g)
initial 0.309 M 0.309 M -
change -x -x +2x
equil 0.309-x 0.309-x 2x
Kc = [HI]^2/[H2][I2]
55.6 = (2X)^2/(0.309-X)^2
at equilibrium,
[HI] = 2X = 2*0.244 = 0.488 M
[I2] = 0.309-0.244 = 0.065 M
[H2] = 0.309-0.244 = 0.065 M
2)
PCl5(g)-------> PCl3(g) + Cl2(g)
equil 0.21
M
0.0502 M 0.0502 M
added - 0.0412 M -
change +x -x -x
equil 0.21+x 0.0914-x 0.0502-x
Kc = [PCl3][Cl2]/[PCl5]
1.2*10^-2 = (0.0914-x)(0.0502-x)/(0.21+x)
x = 0.015
at equilibrium,
[PCl3] = 0.0914-0.015 = 0.0764 M
[Cl2] = 0.0502-0.015 = 0.0352 M
[Pcl5] = 0.21+0.015 = 0.225 M
The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H2(g) + I2(g)...
1) The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.311 M HI, 4.18×10-2 M H2 and 4.18×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.85×10-2 mol of I2(g) is added to the flask? 2) The equilibrium constant, K, for the following reaction is 1.20×10-2 at...
The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H2(g) + I2(g) 2HI(g) Calculate the equilibrium concentrations of reactants and product when 0.293 moles of H2 and 0.293 moles of I2 are introduced into a 1.00 L vessel at 698 K. [H2] = M [I2] = M [HI] = M
The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H2(g) + I2(g) 2HI(g) Calculate the equilibrium concentrations of reactants and product when 0.276 moles of H2 and 0.276 moles of I2 are introduced into a 1.00 L vessel at 698 K. [H2] = _____M [I2] =______M [HI] =______M
The equilibrium constant, Kc, for the following reaction is 83.3 at 500 K. PCl3(g) + Cl2(g) = PCl5(g) Calculate the equilibrium concentrations of reactant and products when 0.249 moles of PCl3 and 0.249 moles of Cl2 are introduced into a 1.00 L vessel at 500 K. [PCl3] = M [Cl2] = M [PCl5] = M The equilibrium constant, Kc, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) = H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and...
The equilibrium constant, Kp, for the following reaction is 55.6 at 698 K. H2(g) + I2(g) 2HI(g) If ΔH° for this reaction is -10.4 kJ, what is the value of Kp at 577 K? Kp =
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.329 M HI, 4.41×10-2 M H2 and 4.41×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.54×10-2 mol of H2(g) is added to the flask? [HI] = M [H2] = M [I2] = M
The equilibrium constant, Kp, for the following reaction is 55.6 at 698 K: H2(g) + I2(g) 2HI(g) Calculate the equilibrium partial pressures of all species when H2 and I2, each at an intitial partial pressure of 1.65 atm, are introduced into an evacuated vessel at 698 K.
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.316 M HI, 4.24×10-2 M H2 and 4.24×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.21×10-2 mol of I2(g) is added to the flask?
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.302 M HI, 4.05×10-2 M H2 and 4.05×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.203 mol of HI(g) is added to the flask?
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.319 M HI, 4.27×10-2 M H2 & 4.27×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.224 mol of HI(g) is added to the flask? [HI] = M [H2] = M [I2] = M please help me!