Question

find missing blanks please!

Experiment 14 Data and Calculations: Heat Effects and Calorimetry A.Specific Heat Trial 1 Trial 2 34.564& 34.56 g Mass of stoppered test tube plus metal 25.734 g 25.734 Mass of test tube and stopper 9.1S0 Mass of calorimeter 9.ISo 4.692 8 Mass of calorimeter and water 48,940 Mass of water Mass of metal 23.6 23.6 C Initial temperature of water in calorimeter Initial temperature of metal (assume 100°C unless directed to do otherwise) Equilibrium temperature of metal and water 25.9 26.0 C in calorimeter C C Atwater (Ffinal-aitial 519 C °C Afetal J J/g°C J/g°C Specific heat of the metal (Eq. 3) Approximate molar mass of metal L02 T Unknown metal # 1&

Answer 1

Mass of calorimeter and water:

For trial 1: 48.940 g

For trial 2: 49.692 g

Mass of calorimeter:

For trial 1: 9.150 g

For trial 2: 9.150 g

So, mass of water:

for trial 1 : (Mass of calorimeter and water - Mass of calorimeter) = (48.940 - 9.150) = 39.79 g

for trial 2 : (Mass of calorimeter and water - Mass of calorimeter) = (49.692 - 9.150) = 40.542 g

Mass of stoppered test tube and metal:

For trial 1: 34.564 g

For trial 2: 34.564 g

Mass of test tube and stopper:

For trial 1: 25.734 g

For trial 2: 25.734 g

So, mass of metal:

for trial 1 : (Mass of stoppered test tube and metal - Mass of test tube and stopper) = (34.564 - 25.734) = 8.83 g

for trial 2 : (Mass of stoppered test tube and metal - Mass of test tube and stopper) = (34.564 - 25.734) = 8.83 g