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3. When 10 mL of 2.0 M HCl is combined with 30 mL of 0.667 M NAOH a temperature change of 6.9 °C was observed. How much heat
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Q 3 ). HCl ( aq ) + NaOH ( aq ) \rightarrow NaCl ( aq ) + H2O ( l )

moles of HCl = ( 2 mol / litre ) x ( 10 x 10-3 litre ) = 0.02 mol

moles of NaOH = ( 0.667 mol / litre ) x ( 30 x 10-3 litre ) = 0.02 mol

total volume = 10 + 30 = 40 mL

mass of solution = density x volume = ( 1.02 gm / mL ) x 40 mL = 40.8 gm

heat evolve by 0.02 mol water = m x s x \DeltaT = ( 40.8 gm ) x ( 4 J / g0C ) x 6.9 0C

= 1126.08 J = 1.126 KJ

heat evolve by 1 mol water = 1.126 KJ / 0.02 mol = 56.3 KJ / mol

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