Homework Answers
Molar mass of Al = 26.98 g/mol
mass of Al = 63.43 g
mol of Al = (mass)/(molar mass)
= 63.43/26.98
= 2.351 mol
According to balanced equation
mol of AlCl3 formed = moles of Al
= 2.351 mol
Molar mass of AlCl3,
MM = 1*MM(Al) + 3*MM(Cl)
= 1*26.98 + 3*35.45
= 133.33 g/mol
mass of AlCl3 = number of mol * molar mass
= 2.351*1.333*10^2
= 3.135*10^2 g
% yield = actual mass*100/theoretical mass
54.72= actual mass*100/3.135*10^2
actual mass=1.715*10^2 g
Answer: 172 g
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