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A block with mass m -6.8 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x 0.22 m
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Solution 1 As the weight is hung the to a distance n-0.22m equilibrium. So, spiry stretches and attains static 1 Efy=0 wuuu G4) Maximum acceleration = w²a = (276) 2 x 0.22 = 2.95 mls?

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