mass m = 7.2 kg
Streachness X = 0.25 m
Velocity at equilibrium position Vo = 4.6 m/s
(1). At equlibrium , mg = kX
from this spring constant k = mg / X
k = (7.2)(9.8)/(0.25)
= 282.24 N/m
(2).Oscillation frequency f = (1/2) [k/m]
= (1/6.28) [282.24/7.2]
= 0.9964 Hz
(3).Velocity of the block v(t) = Vo cos (wt) where w = angular frequency = 2(pi) f = 6.26 rad/s
= 4.6 cos (6.26 t)
velocity at t= 0.39 s is v(0.39) = 4.6 cos(6.26x0.39 rad)
= 4.6 (-0.7649)
= -3.518 m/s
(d). Maximum acceleration = Aw 2
= (Aw)w
= Vo w
= 4.6(6.26)
= 28.8 m/s 2
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