Question

I'm having trouble with 3,4 and 5.

人 。

A block with mass m =6.8 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.23 m. While at this equilibrium position, the mass is then given an initial push downward at v = 5 m/s. The block oscillates on the spring without friction.

1)

What is the spring constant of the spring? 289.74N/m

2)What is the oscillation frequency? 1.039 Hz

3)After t = 0.31 s what is the speed of the block? ______m/s

4)What is the magnitude of the maximum acceleration of the block? ______m/s²

5)At t = 0.31 s what is the magnitude of the net force on the block? _____N

Answer 1

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at equilibrium, KXo = mg k=spring Constant = 6.889.8 - 1997 8.2 = 289.739 N/m 0.23 2) frequency (f) = zelo lectores are zat=W = ft m = f = 1 = 1 | 289.139 = 1.037542) And J 289.739 1 3) at t= 0.3l sec, .. y= Asinat = 0.23 Sin (aft) V = 0.23 yw cop laxft) =0.23x6.5192 Cop (6.5192t) at t= 0.31 sec, v=104994 Cop (6.5192X0-31) radian v=0.65239 m | Upward, I direction. 4) aman = w²A = (6.5192) ² x 0.23=9.7749 m/s2 5) at t=0.31sec, And Fret = mar=mw²y = 2 (6.5192 x 0.23 81h/6-5192x Fret = 59.848 N And