Given:
ΔHo rxn = -133.1 KJ/mol
Hof(N2O(g)) = 82.05 KJ/mol
Hof(H2O(l)) = -285.83 KJ/mol
Balanced chemical equation is:
NH4NO3(aq) ---> N2O(g) + 2 H2O(l)
ΔHo rxn = 1*Hof(N2O(g)) + 2*Hof(H2O(l)) - 1*Hof( NH4NO3(aq))
-133.1 = 1*(82.05) + 2*(-285.83) - 1*Hof(NH4NO3(aq))
Hof(NH4NO3(aq)) = -356.51 KJ/mol
Answer: -356.51 KJ/mol
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