Why Annual Worth Evaluation will give value of a single period if you do repeatability by...
Why Annual Worth Evaluation will give value of a single period if you do repeatability by cash flow ?
Homework Answers
Repetability of the cash flow, means similar set of cash flows repeat, after the completion of the one project period. In this scenario, when annual worth is calculated, then it becomes the annual worth of the years in one single period. It happens, because it is the uniform annual worth and it remains same for each year. Hence, if a project period is 3 years and there are repetability for the 2 project period or 6 years. Then, uniform annual worth for 3 years period will be same as that of 6 year period.
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Why Annual Worth Evaluation will give value of a single period
if you do repeatability by...
Compare alternatives A and B with the present worth method if the MARR is 11% per year. Which one would you recommend? Assume repeatability and a study period of 12 years. $25,000 $10,000 at end of y...
Compare alternatives A and B with the present worth method if the MARR is 11% per year. Which one would you recommend? Assume repeatability and a study period of 12 years. $25,000 $10,000 at end of year 1 and increasing by $1,000 per year thereafter None Capital Investment Operating Costs $55,000 $5,000 at end of year 1 and increasing by $500 per year thereafter $5,000 every 3 years 12 years $10,000 if just overhauled Overhaul Costs Life 6 years negligible...
7. The equivalent annual w $135,578. If the cash flow in $20.000. what is the value of annual worth of an increasin...
7. The equivalent annual w $135,578. If the cash flow in $20.000. what is the value of annual worth of an increasing arithmetie gradient is cash now in year is $30.000 and the gradient amount is value of at an interest rate of 10% per year? [15 marks) G
Compare alternatives A and B with the present worth method if the MARR is 10% per year. Which one would you recommend? Assume repeatability and a study period of 20 years $15,000 $45,000 Capital Inve...
Compare alternatives A and B with the present worth method if the MARR is 10% per year. Which one would you recommend? Assume repeatability and a study period of 20 years $15,000 $45,000 Capital Investment Operating Costs $4,000 at end of year 1 and increasing by $400 per year thereafter $4,000 every 5 years 20 years $8,000 at end of year 1 and increasing by $800 per year thereafter None Overhaul Costs Life 10 years Salvage Value $8,000 if just...
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Compare two alternatives, A and B. on the basis of a present worth evaluation using /= 10% per year and a study period of 8 years. Alternative A B First Cost $-19,000 $-46,000 Annual Operating Cost $-6,000 $-10,000 Overhaul in Year 4 $0 $-3,850 Salvage Value $1,200 $6,200 Life 8 years 4 years The present worth of alternative A is $ and that of alternative B is $ Alternative (Click to select) is selected.
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ACTIVITY: *Determine the cash value of any business using four corporate evaluation methods. The student will:...
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Compare alternatives A and B with the present worth method if the MARR is 11% per year. Which one would you recommend? Assume repeatability and a study period of 12 years. $25,000 $10,000 at end of year 1 and increasing by $1,000 per year thereafter None Capital Investment Operating Costs $55,000 $5,000 at end of year 1 and increasing by $500 per year thereafter $5,000 every 3 years 12 years $10,000 if just overhauled Overhaul Costs Life 6 years negligible...
7. The equivalent annual w $135,578. If the cash flow in $20.000. what is the value of annual worth of an increasing arithmetie gradient is cash now in year is $30.000 and the gradient amount is value of at an interest rate of 10% per year? [15 marks) G
Compare alternatives A and B with the present worth method if the MARR is 10% per year. Which one would you recommend? Assume repeatability and a study period of 20 years $15,000 $45,000 Capital Investment Operating Costs $4,000 at end of year 1 and increasing by $400 per year thereafter $4,000 every 5 years 20 years $8,000 at end of year 1 and increasing by $800 per year thereafter None Overhaul Costs Life 10 years Salvage Value $8,000 if just...
Compare two alternatives, A and B. on the basis of a present worth evaluation using /= 10% per year and a study period of 8 years. Alternative A B First Cost $-19,000 $-46,000 Annual Operating Cost $-6,000 $-10,000 Overhaul in Year 4 $0 $-3,850 Salvage Value $1,200 $6,200 Life 8 years 4 years The present worth of alternative A is $ and that of alternative B is $ Alternative (Click to select) is selected.
ACTIVITY: *Determine the cash value of any business using four corporate evaluation methods. The student will: Corporate evaluation methods *explain why is it important to have a reasonable knowledge of what the firm is worth? *apply the problem data to the four corporate evaluation methods *calculate and compile the results for each method *evaluate and explain the results *determine, prioritize, recommend, and defend the best corporate evaluation method (20 points) Complete the following corporate valuation methods (five) based on the...
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