A basketball team sells tickets that cost $10, $20, or for VIP seats, $20. The team has sold 3320...
A basketball team sells tickets that cost $10, $20, or for VIP seats, $30. The team has sold 3320 tickets overall. It has 296 more $20 tickets than $10 tickets. The total sales are $65,050. How many tickets of each kind have been sold?
here let x,y and z are tickets sold for $10, $20 and for VIP seats category
hence x+y+z =3320 ...........(1)
10x+20y+30z =65050...(2)
y=296+x .............(3)
solving above three equations:
number of $10 tickets =1053
number of $20 tickets =1349
number of VIP tickets =918
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