A basketball team sells tickets that cost $10, $20, or, for VIP seats, $30. The team has sold
3067 tickets overall. It has sold 181more $20 tickets than $10 tickets. The total sales are $57,410.
How many tickets of each kind have been sold?
How many $10 tickets were sold
How Many $20 tickets were sold
How Many $30 tickets were sold
let x,y and z are $10 ,$20 and $30 tickets
therefore x+y+z =3067 ...........(1)
10x+20y+30z =57410 .......(2)
y=x+181 ...........(3)
solving above:
number of $10 tickets x =1093
number of $20 tickets y =1274
number of $30 tickets z =700
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