Homework Answers
1) Gravitational potential energy of mass m at height, h =mgh
Hence gravitational potential energy of ball at highest position
= 0.2*9.8*13.9 = 27.2 J
2) As no energy is lost in air, kinetic energy of ball just after leaving the hand is converted to potential energy at highest point. Hence kinetic energy of ball just after leaving the hand
= 27.2 J
3) Kinetic energy of ball as it returns, is again 27.2 J, as there is no change in it's potential energy on returning and there is no loss of energy in air.
4) Kinetic energy = mv^2/2
27.2 = 0.2*v^2/2
v = 16.5 m/s
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