Question

013 (part 1 of 2) 10.0 points In an experiment designed to measure the strength of a uniform magnetic field produced by a set of coils, electrons are accelerated from rest through a potential difference of 323 V. The resulting electron beam travels in a circle with a radius of 6.96 cm. The charge on an electron is 1.60218 x 10-19 C and its mass is 9.10939 x 10-31 Assuming the magnetic field is perpendic- ular to the beam, find the magnitude of the magnetic field. Answer in units of T. kg. 014 (part 2 of 2) 10.0 points What is the angular velocity of the electrons? Answer in units of rad/s.

Answer 1

Ansö Giren :- 9.10939 X10'' X 1,06569 X107 Polen Hal differance v 323 V radius o arde r=6.96 cm = 6.968 102 m change an e a = 1.60218 × 10-19 C mass of e- me = 9.10939 x 10-31 kg. Part ② ; -, Now, from conservation of energy U KE Nespeed of é qv= 1 me uz २ 2²= zav me me 2x 1,60 218 x 10-19 X 323 = 1.0659 x 10 m/s. 9.10939 x 1031 Now conloppetal parce neccesary is provided by magnelse force B 1.60218 x 10 19 X 6.968 102 v=2qV muz qUB 7 r magnetic field B mu ar - B = 8.70562 x 10-4 T

Part 2 :- angular kelocity co e e- ale r w = 1,0659x107 6.96 8 10-2 W = 1,53146 X 10% rad /s