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A person exerts a horizontal force of 30 N on the end of a door 92...

A person exerts a horizontal force of 30 N on the end of a door 92 cm wide.

a) What is the magnitude of the torque if the force is exerted perpendicular to the door?

b) What is the magnitude of the torque if the force is exerted at a 70.0 ∘ angle to the face of the door?

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Answer #1

Given data The force is, F = 30 N The radius is, r = 92 cm=0.92 m a) The torque is, T =rF sin =(0.92)(30) sin(90) = 27.6 N.m

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