Torque (t) = r*F*sin(theta)
A)-
So, r= 1.05/2 = 0.525m
Torque = 0.525 * 51.5 * sin(90) = 27.0374 Nm = 27.04Nm
B) - if r=1.05m
Then . Torque = 1.05* 51.5* sin(90) = 54.075 Nm = 54.08Nm
plz upvote
(a) A person opens a 1.05 m wide door by pushing on it with a force...
7. 00 points 1 Previous Answers SerCP118.1 P.001 A janitor opens a 1.50 m wide door by pushing on it with a force of 58.5 N directed perpendicular to its surface. HINT m) does he apply about an axle through the hinges if the force is applied at the center of the door? (a) What magnitude torque (In N 75 x Nm from the hinges? (b) What magnitude torque (in N.m) does he apply at the 50.000XN.m
3. 8/16 points Previous Answers SerCP11 8.1.P.001. В му A doctor opens a 1.25 m wide door by pushing on it with a force of 39.5 N directed perpendicular to its surface. HINT (a) What magnitude torque (in N.m) does she apply about an axis through the hinges if the force is applied at the center of the door? 24.69 Nm (b) What magnitude torque (in N.m) does she apply at the edge farthest from the hinges? 59.25
A student opens a 12.0 kg door by applying a constant force of 40.0 N at a perpendicular distance of 0.900 m from the hinges. If the door is 2.00 m in height and 1.00 m wide, what is the magnitude of the angular acceleration of the door? (Assume that the door rotates freely on its hinges.) The moment of inertia for a door about the hinge is I = -mr2.
A 21kg solid door is 220 cm tall, 92cm wide. 1.What is the door's moment of inertia for rotation on its hinges? 2.What is the door's moment of inertia for rotation about a vertical axis inside the door, 13cm from one edge?
A torque RF is applied on a door by pushing with a perpendicular force F at a distance R from the hinge (axis of rotation), which of the following will increase the magnitude of the torque? Mark all that apply. a. Move force F closer to the axis of rotation. b. Move force F farther from the axis of rotation. c. Apply force F parallel to the moment arm. d. Apply force F at an angle of 30 to the...
If a force of 2.00 N is needed to open a 70.0 cm wide door when applied at the edge opposite the hinges, what force must be applied to open the door if you push against the door 40.0 cm from the hinged side?
A person exerts a horizontal force of 30 N on the end of a door 92 cm wide. a) What is the magnitude of the torque if the force is exerted perpendicular to the door? b) What is the magnitude of the torque if the force is exerted at a 70.0 ∘ angle to the face of the door?
part c=d How much force must you and your friend each apply to the free end of the door on the same side and perpendicular to the plane of the door in order to produce the same torque as that produced by both of you in part (a) above? N (d) What is the angular acceleration of the door? rad/s2 A heavy swing door has a mass of m = 7,500 kg, a width W = 1.9 m, and a...
Two equal-magnitude forces are applied to a door at the doorknob. The first force is applied perpendicular to the door, and the second force is applied at 30° to the plane of the door. Which force exerts the greater torque about the door hinge? Both forces exert zero torque. the second force (applied at an angle) the first force (applied perpendicular to the door) Both forces exert equal the same non-zero torque.
A person exerts a horizantal force of 85 N on the end of a door 77 cm wide. part A What is the magnitude of the torque if the force is exerted perpendicular to the door? Express your answer using two significant figures.