here,
initial speed , u = 56.3 km/h = 15.64 m/s
the distance of deer from the car , s = 23.6 m
let the acceleration be a
time taken , t = 2.6 s
using seccond equation of motion
s = u * t + 0.5 * a * t^2
23.6 = 15.64 * 2.6 + 0.5 * a * 2.6^2
solving for a
a = - 5.048 m/s^2
using first equation of motion
the final speed of car when the deer was struck , v = u + a * t
v = 15.64 - 5.048 * 2.6 m/s
v = 2.51 m/s = 9.04 km/h
If the truck hits the deer 2.60 seconds after the driver slams on the brakes, what...
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