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Attention: Due to a bug in Google Chrome, this page may not tunction correctly, Click here to learn more. Attention: Due to a bug in Google Chrome, this page may not function correcty Caick here to learn more. 4. Gravetter/Wallnau/Forzano, Essentials - Chapter 8- End-of-chapter question 6 Aa Aa Ackerman and Goldsmith (2011) report that students who study from a screen (phone, tablet, or computer) tended to have lower quiz scores than students who studied the same material from printed pages. To test this finding, a ssor identifies a sample of n 16 students who used the electronic version of the course textbook and determines that this sample had an average score of M-72.5 on the final exa the final exam scores for the general population of students taking the c deviation of σ = 8 and formed a roughly normal distribution. The professor would like to use the sample to determine whether students studying from an electronic screen had exam scores that are significantly different from those for the general population. m. During the previous three years ourse averaged-77 with a standard Standard Normal Distribution Mean 0.0 Standard Deviation 1.0 500O 599 1.0 2.0 3.0 3.0 2.0 O Type here to search

+3.0 2.0 1.0 0.0 0.00 1.0 2.0 3.0 Assuming a two-tailed test, state the null hypothesis in a sentence that includes the two variables being examined. The null hypothesis states that studying on an electronic screen has a significant effect on final exam score Using the standard 4-step procedure, conduct a two-tailed hypothesis test with α-05 to evaluate the effect of studying on an electronic screen. 72.5 Step 1. Ho : μ = 72.5 ;Ha: μ Step 2. The critical region consists of sample meanswithin1.96 Step 3, For these data the standard error is 15.00 , and z = 1.33 , Step 4. Fail to reject the nul hypothesis, and conclude that studying on an electronic screen on final exam score. which is in the critical region. has an effect Graded O Type here to search

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Population Mean 77 Population Standard Deviation o 8 Sample Mean =X = 72.5 n-16 The null hypothesis states that studying on an electronic screen does not have a significant effect on final exam score Step 1 The null and alternative hypothesis are HI : 77 Step 2: α-0.05 We find the z-critical value using Excel function NORM.S.INV for a two sided test a/2 0.025 z-crit- norm.s.inv(0.025, true) z-crit 1.96 The critical region consists of sample means outside of ±1.96 Taking positive value alu nnota Step 3: Standard Error is given by SE (72.5-77) 8 (x- μ) - -2.25 16 For these data the standard error is 2, and z --2.25, which is in the critical region Step 4: Since z--2.25 <-1.96, it falls in the crirical region, hence reject Ho Thus, Reject the null hypothesis, and conclude that studying on an electronic screen has an effect on final exam score

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