Question

calculate the number of moles of BaF2 in a 10.0g sample

Experiment 9 Molar Mass of a Volatile Liquid 75 Date: Name: Experiment 9 Molar Mass of a Volatile Liquid Questions and Problems (May be assigned before or after the experiment, depending on your instructor.) (Show all calculations where appropriate.) 1. Show your work and convert: a) 25.0°C to K b ) 300 K to °C c) 750 torr to mm Hg KERST 25B 300-C+273.15 Ke 298.15 -273.15 24.85=0 d) 701 torr to atm e ) 0.890 atm to torr f) 250 mL to L g) 0.750 L to mL

Answer 1

I show your work and convert @ 25°C to K Explanation 25°C PS equal 0°C +273.15 = 273.15 K to 298.15 K. Then 25° C as 25 + 273:15 = 298.15k 6. 3ook to °C Explanation 0°C +27315 = 273.156. 300k is equal to 26.85 °C E 27 °C X°C + 273.15 = 300k XC = 300K -273.15 xºc = 26.85 ② 750 forr mm Hg. Explomation TO = millimetreofregare 750 torr is equal to 150mm ttg Torr= mm Hg 750 = m.m. He d. Tol tony to atm Explanation Tora Alma Yol torr as equal to 0.922368 760 Atm = 701 760

@ 0.890 atm to 10:17 0.890 atm is equal to 676.4 707107 Explanation Atm = Torr 760 Toror = Atm X 760 = 0.8908760 = 67604 if 250 mL to L. Explonation 250. mi is equal to 0.25 11 = 1000 mL 1000 mL IL 250 mL ? ? = 250 tooo ? = 0.25 @ 0.150 L to mL 0.750L 95 equal to 750 mL Explanation 1 L 1000mL 0.750L G 7 ml ? mL- 0.750X1000 ? mL = 750ml