Question

Please help! Equation 11 and 3 are posted below the main picture!

Rotational Mechanics Pre-Lab Assignment (1 point) 1. Consider a solid sphere and a solid disk with the same radius and the same mass. Explain why the solid disk has a greater moment of inertia than the solid sphere, even though it has the same overall mass and radius. 2. Calculate the moment of inertia for a solid cylinder with a mass of 100g and a radius of 4.0 cm. 3. In this question you will do some algebra to determine two relations that you will need for Part 2 of this lab. Write down Eq. 11 twice. In the first statement, set the rotational kinetic energy term equal to zero (i.e. 1/210 = 0) - call this your "No Krot model”. Leave the second as it is written in Eq. 11 - call this your "Krot model”. For both models, solve for v in terms of g, h, and a. In the Krot model, you will need to use / = kmr2 (Eq. 3) and = v/r. The solution for the Krot model will have a k term as well. Once you have solved for v, use the kinematic relation, v = at, and solve for t for both models separately. These two solutions represent the predicted time it will take an object to descend a height, h, down an inclined plane when you assume all kinetic energy in the system is translational (No Krot model) and when you assume the kinetic energy is distributed between translational and rotational motion (Krot model).

Answer 1

Please see image and try to understand thanks

Ia mre? Iz ŹMRZ In Ring all mas is distributed at r distance from center but on solid sphere mass es distributed Rs whole body so thong distance is varies for each mass eleront of sphere so overall mer2 term is less they ring in solid sphere I-a mora - Î x0.1 X(0.04)? = 8x105 kp.ma

- energy Consovation Ex = Ep - UI + kg = Up the 3 mgh +0=0 + Ź muza Tw 0 03 Wzo No Rotation" moghz zmus a, vo vzgh 1. v= at = to u = ran a I Rotation motion - mgr = 1 mu? + 2 x km 922 x H 1 g 20h= 12 + kva to s hare