Based on the following information, what is the AH for this reaction: NO(g) + O3(g) -...
Question 62 Calculate the enthalpy change for the following reaction: NO(g) + O(g) - NO2(g) from the following data: NO(g) + O3(g) – NO2(g) + O2(g) O3(g) – 1.502(g) O2(g) - 20(g) AH = -198.9 kJ AH = -142.3 kJ AH = 495.0 kJ 0-304.1kJ 438.4 kJ 190.9 kJ 153.8 kJ O -551.6 kJ
Calculate the enthalpy change for the reaction NO(g) + O(g) → NO2(g) from the following data NO(g) + O3(9) → NO2(g) + O2(g) ΔH=-198.9 kJ/mol O3(g) → 1.5O26(g) ΔH=-142.3 kJ/mol O2(g) → 2O(g) ΔH = 495.0 kJ/mol A. 153.8 kJ B. 190.9 kJ C.-551.6 kJ D.-304.1 kJ E. 438.4 kJ
1) Find the AH of the following reaction: C(s) + O2(g) à CO2(g) Given the following data: Sro(s) + CO2(g) à SrCO3(s) 2Sro(s) à 2Sr(s) +0,(8) AH = -234 kJ AH = +1184 kJ 2SCO,(s) à 25r(s) + 2C(s) + 302(g) AH = +2440 kJ 2) Find the AH of the following reaction: 3NO,(g) + H2O(l) à 2HNO,(aq) + NO(g) Given the following data: 2NO(g) + O2(g) à 2NO(g) AH=-116 kJ 2N2(g) + 502(g) + 2H2O(l) à 4HNO3(aq) AH =...
Given the following data, 2 O3(g) ----> 3 O2(g) ∆rH = -377.00 kJ mol-1 O2(g) ----> 2 O(g) ∆rH = 545.00 kJ mol-1 NO(g) + O3(g) ----> NO2(g) + O2(g) ∆rH = -124.00 kJ mol-1 Determine ∆rH for the reaction, NO(g) + O(g) ----> NO2(g) ∆rH = ? kJ mol-1
Ozone (O3) in the atmosphere can react with nitric oxide (NO): 03(g) + NO(g) --> NO2(g) + O2(g). (AH° = -199 kJ/mol, 45º = -4.1 J/K·mol) Write answers to three significant figures. a. Calculate the AG°(K9/02.) for this reaction at 25°C. b. Determine the temperature(°C) at which the reaction is at equilibrium.
physical chemistry 2. The bond dissociation energy of oxygen gas is 495 kJ/mole, while the enthalpy of formation of ozone gas (O3(g))is 142.3 kJ/mole. For the reaction: NO +O3(g) NO2(g) + O2(g) it is found that AH = -198.9 kJ/mole, Determine the enthalpy change for the reaction: NO(g) + O() NO2(8)
Enter your answer in the provided box. Calculate the amount of heat (in kilojoules) associated with 172 g of mercury cooling from 115.9°C to 12.5°C. The specific heat of mercury is 0.139 J/g.°C. Do not include a sign in your answer. Given the following information: NO (g) + O (g) --> NO2 (g) AH =-198.9 kJ/mol 20 (g) --> 202 (g) AH = 495.0 kJ/mol What is AH in kJ/mol for NO (g) + O2 (g) --> NO2 (g)? 446,4...
Ozone (O3) in the atmosphere can react with nitric oxide (NO): O3(g) + NO(g) --> NO2(g) + O2(g). ( ΔH° = –199 kJ/mol, ΔS° = –4.1 J/K·mol) Write answers to three significant figures. a. Calculate the ΔG°( kJ/mol) for this reaction at 25°C. b. Determine the temperature(oC) at which the reaction is at equilibrium.
Ozone (O3) in the atmosphere can react with nitric oxide (NO): O3(g) + NO(g) --> NO2(g) + O2(g). ( ΔH° = –199 kJ/mol, ΔS° = –4.1 J/K·mol) Write answers to three significant figures. a. Calculate the ΔG°( kJ/mol) for this reaction at 25°C. Blank 1 b. Determine the temperature(oC) at which the reaction is at equilibrium.
From the following equations, calculate AH for the reaction 2N2(g) + + 5O2(g) → 2N2O5(g) AH = ? H2(g) + O2(9) H206) AH = -285.8 kJ N2O5(g) + H200 2HNO30 AH = -76.6 kJ N2(g) + 302(g) + H219) - 2HNO30) AH = -348.2 kJ