Question

In outer space rock 1 with mass 9 kg and velocity <3400, -3100, 3400> m/s, struck rock 2, which was at rest. After the collision, rock 1's velocity is <2900, -2300, 3700> m/s. What is the final momentum of rock 2? P 2 = > kg-m/s Before the collision, what was the kinetic energy of rock 1? Kli= Before the collision, what was the kinetic energy of rock 2? K2 = After the collision, what is the kinetic energy of rock 1? Kur = Suppose the collision was elastic (that is, no change in kinetic energy and therefore no change in thermal or other internal energy of the rocks)- In that case, after the collision, what is the kinetic energy of rock 2? Ky = On the other hand, suppose that in the collision some of the kinetic energy is converted into thermal energy of the two rocks, where AEhrmal + AE bormal = 9.61 X 106. What is the final kinetic energy of rock 2? Ky = In this case some of the kinetic energy being converted to thermal energy), what was the transfer of energy Q (microscopic work) from the surroundings into the two-rock system during the collision? (Remember that represents energy transfer due to a temperature difference between a system and its surroundings.) Q=

Answer 1

me 9 kg, Upx = 3400m/s, My -3/00m/s, 42 = 3400w/ Usa = ours, Uzy = ours, 122= ouls Vix = 2900m/s, viy = – 2300m/s, z = 3700 w/ Nowo, Applying conservation of lineas momentum Pin the = pi + Part => 9 < 3400,-3100, 3400% +0 = 9x2900,-2300, 3700) + ? -> Pad - 9 <3400-2900, -3100 +2300, 3400 - 3700) =) Pet = <4500,-7200,- 27007 kg-m/s Kinetic energy of socks before collision Kia žm, ut a&xq(V2400)*+ (3/0052 +8400327 kii = 147285000 J 21.47x108) Kinetic energy of rock 2 before collision Kai = 1 mx 0² 207 kinetic energy of rocks after collision kef = 12 m, v² = 2X9 X{12900²42300 )² +37002) Kit = 123255000 J - 1.23X10ⓇJ

Kinetic energy of rock 2 after collision Here collision is elastic, so, no loss of ke =) K.E lost by rock b = K.E gained by sock 2 => 147285000 --123255000 = K24-0 -> K24 = 24030000J = 2:40x1071 kaf when there will be thermal loss Kaf = 2.40x107_9.61×106 = 1.44x107J