Question

In outer space a rock with mass 7 kg, and velocity <4000, -2800, 1800> m/s, struck a rock with mass 12 kg and velocity <210,-290, 340> m/s. After the collision, the 7 kg rock's velocity is <3500, -2100, 2300> m/s. What is the final velocity of the 12 kg rock? > m/s What is the change in the internal energy of the rocks? AEinternal = Which of the following statements about Q (transfer of energy into the system because of a temperature difference between system and surroundings) are correct? (Ignore heat transfer by radiation.) Check all that apply: 0 because there are no significant objects in the surroundings. Q = AEinternal of the rocks. O Q= AK of the rocks. O O because the duration of the collision was very short.

Answer 1

con Page 13 Uz mi m2 12kg 7Kg After collision | ✓ = 4000 î . - 2800 + 1800 ☆ mis W X = 1 21 ( - 230 / + 34 0 6 1 3 + V - 35e 0 - [bo + 23 Đo & PH 5. momentum is conserved - Pinitial = Pfinal miu + mau = mina + ma u u ma uz = micul ) + mau = 12 T = 7 [ 14000 – 3500) Î + (-2800+ 2100)j + (1800-2300) * + 12 [210 € - 290 § + 340 Â ] → Y = Wiz [ 500 i +-700 I – 500 ] + 1412 [ 2101 - 2909 +340% ] ū = 501.66 î – 678.33 9 + 48.33 Å . I have taken Vf' as uz & Vf = Uz = 501066 - 698-33, 48 337

Page TV1 = V = (4000)2 + (2800)2 + (1800)2 V = 5203.8447 mis .. V2 = (3500)2 + (2100)2 + (2.30012 2. V2 - 4685.0827 ms i u ar (210)2 + (2907² +134012 4 - 493.761 mis .. 0 42 = VA = 1501.66)2 + (6.38.33)2 + (48.33) " U2 = vf = 861.1987 m3 " Energy is conserved I miv? + / m2 42 = ½ min + / m2 4 + Erinte 2 => 7 [V, 2-VT + 12 [42-UT = DE internal Einterned = 7(1520368 047)2- 14685.0827) + 12 [ (493•761) – (8 67 • 1987)?T = 3.59 8107 - 0.5974 x 107 Einter = 2099 2x 107 T 1. Q = DE internal of the socks = ok of the rocks [8 AE internal Z AK)