Question

10) Determine the electron count and oxidation states of the following complexes: COCOR PM.,,,CI, UP Lp-cp- R2 co co R2 d) O-PR2 e) [Fe(bpy)3]3+ f) TpRe(dppe)(CO) -Ni-H VO OC "CO O-PR2

inorganic chemistry

Answer 1

- hydrogen ha хvез 8 all o Тр/ 1. To answer this question we need to consider the group number of Metal (M) 2. Formal charge of metal comprens and elections contribution by eachligando a. Ti belongs to group 4, yo gering makes it Ti 34 each ring contributes de Now we will do electron counting - each ferocene • 2 rings 12€ Total Ibé so, Ti işin ts oridation State and total number of There is no over charge on the comprex stig neutral) e are 13. contributes & electrons eleton pait with other mo, each contributes 4 é o "Mo belongs to groups, and Chloride in leaves as do So this give me also Mo it sharing eleton pair with other mogen each phosphine contributes gé we have 2 of them for Mo so te from phosphines, Similarly each cocontributes L ē we have a of them so 4e; over electon count : set 4 é thé : 12 e formo so, Mo is in ti state in complex and there are 12e, over the complex has no charge

C. "Mo belongs to group6, so do(66), each co contributes gé, So we have be from co , also benbene contributes 60" Sover all we have 6+6+6 é = 18€ No charge for mo, and complexe is neutral. Ni belongs to group io, carbon bond from benzene and hydride adds a positive charges sonjat = do = sé from Nickel. each pRg adde 2e so 4e from them. Over all 10 é Ni has f2 charge in the complen , but complen itself is neutral. e. ffelbpy)," te belongs to group 8, fest means sé from metal. boy is bippyridiene Love Nitrogen complears with Fe and they contributes té for each bly. We have 3 bpy =) izé. Over elecbow Count : 12+5=1té Iron oxidation state = 3+ Over all complen it positively charged. DPY

nd colatributel te gara f. Tp the (appe) (60) * Tp is a ligand called trispyrazolglborate seaculigan * appe is a ligand called ',2-Bis(diphenysphosphino) ethane. co contributes ae- y each ligand contributes 4é * Re belongs to groupf. So té So, overall electron count = 17e Re has no onidation state and complex has no formal charge.