Question

For each of the following complexes draw the structure, determine the electron count at the metal centre (use the neutral lig

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Answer #1

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Ta (ƞ5-C5H5)(CH3)3

d electron count at metal center = 5

oxidation state of the metal = 0

ligand contribution

ƞ5-C5H5 = 5 * 2 = 10

CH3 = 1 * 3 = 3

Total electron count = 5+10+3 = 18 electrons

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[Ni (ƞ1-C3H5)(PPh3)(CO)2]-

d electron count at metal center = 10

oxidation state of the metal = -1

ligand contribution

ƞ1-C3H5 = 1

PPh3 = 2

CO = 2*2 =4

Total electron count = 10+1+2+4+1 = 18 electrons

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[Mn (ƞ6-C6H6)(CO)3]

d electron count at metal center = 7

oxidation state of the metal = +1

ligand contribution

ƞ6-C6H6 = 6

CO = 3*2 =6

Total electron count = 7+6+6-1 = 18 electrons

C13 Czo

[Ru (PMe3)2(CHPh)Cl2]

d electron count at metal center = 8

oxidation state of the metal = +2

ligand contribution

(PMe3)= 2*2 =4

Cl = 2*1 =2

CHPh = 2

Total electron count = 8+4+2+2 = 16 electrons

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[Co(µ2-CO)(CO)3]2

d electron count at metal center = 9

oxidation state of the metal = 0

ligand contribution

2-CO)= 2

3CO = 3*2 =6

Metal-metal bond = 1

Total electron count = 9+2+6+1 = 18 electrons

At higher temperature a typical bond vibration is observed, The axial ligands of trigonal bipyramidal or square bipyramidal geometry exchange with the equatorial ones.

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