Question

(1) Name the following complexes and determine the oxidation number of central metal atoms (9 points) (a) [Ni(CN).] (b) [Co(Cl)] (c) [Mn(NH)]

Answer 1

solution (a) [Nile Nae The Centrol atom is Nickel, The ligand Atached to the Nickel is cyano (CN). 4 cyano ligands are present le tetra cyano. where the onidation number of CN is - Number we have to find one onidation os Nickel Ni + 4 x-1 = -2 Ni = -2+1 Onidation Number of Nickel & 2. Name of the complen is Tetracyano Nickelatie (W) ion Hence, onidation Number of the Central atom Nickel is ta and the name of the Complen is Tetracyano Nickelate (II)ion. (b) [co (C4) I The Centroal atom is Cobalt, The ligand . Attached to the Cobalt is chloro (cl). 4 chloro ligands are present, i.e Tetrachloro. where the onidation Number of cl is -

we have to sind the onidation Number of Cobalt. Cot 4x1 = -2 Co = -2+4 = 2 The Onidation Number of Cobalt is a Name of the Complen is the trachloro cobaltatie Cuba Hence, the onidation number of the central atom Cobalt is ta and the name of the Complen is Tetrachloro cobaltatie (1). 10 Mn CNH3) The Central atom is Manganese, the ligand Attached to the Manganese is Ammine (NH3). 6 Ammine (NHg) ligand are present, ie hena ammine Alte is a nuetrol molecule and the onidation - number is zero. . we have to sind the onidation Number of Manganese Mn + 6Xo = ta Mn = +2 (we can also use x in the place of centaal atom to sind it onication number) Onication Name of Number of Manganuse is at .. the complen is hima ammine manganate (1)

Hence, the manganese Complen is onidation number of centrol atom is ta and the Name of the tena ammine Manganate cu).