Question

(1) Name the following complexes and determine the oxidation number of central metal atoms (9 points) (a) [Ni(CN).] (b) (Co(Cl)] (c) [Mn(NH)] (2) Palladium (II) to form complexes with coordination number 4. A compound has the composition PdCI,.3NH,. (a) Write the formula for the compound that best shows the co-ordination structure. (b) When an aqueous solution of the compounds is treated with excess AgNO,(aq), how many moles of AgCl(s) are formed per mole of PdC1,.3NH, (2+2 points)

Answer 1

1) Before naming the complex compound we have to go through following instructions.

A) Cation should be named before anion.

B) Ligand should be named before metal ion in alphabetical order.

C) for anionic ligands which ends with ite, ate etc then replace it with ito,ato respectively.

D) number of each type of ligand is representated by mono, di , tri , etc or bis, tris, etc.

E) after naming of ligand is completed, naming of central metal atom starts. For cationic complex ion , name of central metal will be same as the element. Ex- Ni is known as nickel.

For anionic complex ion, name of the central metal ends with suffix ate. Ex - Cu is Known as cuperate.

For determination of oxidation number some rules should be kept in mind-

1) an element which is free in state has a 0 oxidation number

2) oxidation state of group 1 is +1 whereas group 2 has +2 oxidation state. Group 17 has -1 oxidation state if the element is in binary compound.

Let's take an example of Ni(Co) 4

Let Ni be x

We know that oxidation state of CO is 0

Therefore x+4× 0 = 0

Keeping in mind the above given rules :::

1a)[Ni(CN)4] -2

Name of the compound is tetracyanonickelate (II) and oxidation state is --> let Ni be x

Since oxidation number of -CN is -1

x + 4 × -1 = -2==>> x= +2

1)b) [ Co(Cl4)] -2

Name of the compound is tetrachlorocobaltate (II) and oxidation number is - let Co be x

Oxidation number of Cl is -1

x + 4 × -1 = -2

x = 2

1)c) [Mn(NH3)6] +2

Name of the compound is hexaamminemanganese (II)

Since NH3 has neutral oxidation state therefore

Oxidation state = x+0= 2

Therefore oxidation state of Mn is +2

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