Question

100 Experiment 12 Determination of Solution pH 2. Provide equations for each of the following. (Use compounds from question 1. if you want a) Dissociation of a strong base in water b) Dissociation of a strong acid in water c) lonization of a weak base in water d) lonization of a weak acid in water e) Autoionization of water _ M 3. A 5.0 M solution of HCl in water has a proton concentration of M. 4. A 0.01 M aqueous NaOH solution has a hydroxide concentration of 5. An aqueous HCl solution has a proton concentration equal to 6,00 mol/L. The HCl concentration in this solution is M . 6. An aqueous NaOH solution has a hydroxide concentration equal to 0.02 mol/L.The NaOH concentration in this solution is M. 7. The pH of an aqueous solution is 4. a) The pOH of this solution is -

Answer 1

= @ Dissoeiation of a Strong base in Waley > NaOH is a strong base, So equation is Na0H69+Ho Ow → nat ohfaq) 6 Dissociation of a strong acid in water » Hel is a strong acid, so equation HCl + H 0 H₂O + Co . 6 Ionization of a weak base in water - NHQ (aq) + H20 (1) È MHz (aq) +O4 (aa)

@ Bonisation of a weak aciden Wales 3 CH₃ COOH + H2O CAO + H30 @ Autolonisation of water Ho4 Həр , орон 3 A 5.0M solution of Hel in water has a proton concentration of 5.0 M (He is strong neid, So dissociate Completely ) 7 A 0.01 e aqueous NaOH solution has a hydroxide concentration of 0.01 M. (Naol is strong base, so discoenite completely 5 t aqueous Hel solution has a proton Concentration equal to 6.00 moill. The tel. concentration in this solution is 6.00 M. Hel, is strong acid, so dissociate completely [HIJ = 600mol/means [Hel] = 6:00 MALL = 6 M 7 6 An aqueous NaOH Solution has a hydrovide concentration equal to 0.02 molsh. The NaOH Concentration in this solution is 0.02 M. TNOoh is a strong base, so dissociate completely. [04-7 = 0.02 moll means [NaOH7 - 0.02 mo)2 = 0.02 M 7 7 The pH of an que aqueous solution is 4. DHP OH = 14 So pot - 14-pH - 20 so the = 14-4 = port of the 10 solution is 10.