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How many moles of NO₂ would be required to produce 8.94 moles of HNO₃ in the...

How many moles of NO₂ would be required to produce 8.94 moles of HNO₃ in the presence of excess water in the following chemical reaction? 3 NO₂ (g) + H₂O (l) → 2 HNO₃ (g) + NO (g)

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Answer #1

From balanced chemical equation,
Mol of NO2 required = (3/2)*moles of HNO3 reacted
= (3/2)*8.94 mol
= 13.4 mol

Answer: 13.4 mol

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