Question

How many grams of CuO would be required to produce 10.0 moles of nitrogen gas in the following chemical reaction? 2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N2(g) + 3 H2O(g)

Answer 1

Allo) givere : 2 NH2(g) + 3640 (s) 3((3)+ N₂ (9) + 3H₂0 (9) from ean , it is clear that the molar ratio of co to Ne is 3:1. given: Moles of Na- 10.0 moll Thus, Moles Of Cub= Moles of N2 x 3 malcyo I molN2 = 10.omöluz x 3 molluo IMON2 = 30.0 mol cuo we know that Molar mass of Cao = 79.545 g/mol Mass of Cuo= Moles of Cuox Molar mass of Cuo = 30.0 mon fuo x 79.5459 imorgo = 2386 35 guo = 2390 g Cuo

Als given: Naat 3H2(g) 2NH3 (9) (2) from ean (2), the molar ratio of NH3 to Na es 2:1 given; Moles of Ng = 3.76 moles Moles of NH₃ = Moles of N2X amol NH3 I molN2 = 3.76 m2N2 x a mol NH3 i molna = 7.52 mol NH3