As the proton is positively charged. the force will be in the downwards direction. We use the kinematics equations with the mass of the proton
w =EeL²/ 2mvₓ² =
= 364 x1.6 x10⁻¹⁹ (.02)² /2 x 1.67x 10⁻²⁷ x(1.6 x10⁶)²
w=2.72 x10⁻⁶ m
the proton will displaced 2.72μm downwords
all the data has been taken from standard question
E can be calculated as follows
If the proton would not hit one of the plates, what would be the magnitude of...
When the particle exits the region between the plates, what
will be the magnitude of its vertical displacement from its entry.
( in mm)
lass Management | Help ectrostatic Charge Begin Date: 1/17/2018 4:01:00 PM-Due Date: 1/25/2018 11: (1000) Problem 2: A particle with charge q = +4e and mass m-76x 10-26 kg is injected horizontally with speed 1.9x106 m/s into the region between two parallel horizontal plates. The plates are 26 cm long and 1.3 cm apart. The particle...
A proton moving at 3.0 106 m/s passes into the region between two parallel conductors. The region between the plates has a constant electric field pointing to the right of magnitude 2.0 x 104 N/C. a) what acceleration does the proton experience between the plates? b) if the plates were 3 cm apart what is the speed of the proton as it exits the plates?
3. A proton enters a uniform electric field created by two charged parallel plates, as in the diagram below. The electric field is uniform and has a magnitude is 2000 N/C. (a) Transfer the diagram to your answer sheet and show clearly which plate is positively charged and which is negatively charged. (b) Draw the electric force acting on the proton. (c) Calculate the acceleration of the proton. (d) Calculate the time the electron spends in the electric field if...
The deflection plates of an ink-jet printer are set up horizontal and parallel one above the other; both are square, of side 4.0 cm. They are charged such that the electric field in the region between them is uniform, pointing vertically downwards, and of magnitude 10.0 × 106 NC–1. An ink drop of mass 5.0 × 10–10 kg and charge –1.0 × 10–13 C enters the region between the plates, travelling horizontally at 25 ms–1 parallel to a side of...
A proton traveling to the right moves in between the two large
plates. A vertical electric field, pointing downwards with
magnitude 3.0N/C, is produced by the plates.
What is the direction of the force on the proton?
Draw the electric field lines on the diagram.
If the electric field is 3.0N/C, what is the acceleration of
the proton in the region of the plates?
Pretend the force of gravity doesnot exist; then sketch the
path of the proton.
We take...
A proton moving at v0 = 1.70 ✕
106 m/s enters the region between two parallel plates
with charge densities of magnitude σ = 2.60 ✕
10−9 C/m2 (see the figure below).
A uniform electric field is produced by two charged horizontal
plates, each of length d, where the positive plate is
above the negative plate. The leftmost side of each plate is at
horizontal position x = 0. The upper plate has charge
density +σ and the lower plate...
Two 1m X 1m conducting plates are spaced 10cm apart and oriented horizontally ( each plate is parallel to the floor). A 15V battery is connected to the plates with the positive terminal connected to the lower plate. 1) What is the electric field (magnitude and direction) between the plates? Explain 2) What is the total charge on the upper plate? (sign and magnitude) Explain. 3) What is the capacitance of the two plates? A proton is released midway between...
A proton with a speed of 2.20×106
m/s is shot into a region between two plates that are separated by
a distance of 0.185 m. As the drawing shows, a magnetic field
exists between the plates, and it is perpendicular to the velocity
of the proton. What must be the magnitude of the magnetic field (in
T), so the proton just misses colliding with the opposite
plate?
what are the steps and formulas to acquire this answer?
The electric field in the region between two oppositely charged, parallel, conducting plates has a magnitude of 250 N/C and the plates are separated by a distance of 20 cm. A) calculate the surface charge density on each plate and B) the acceleration of a proton if it is placed 5 cm from the positive plate and released from rest
The electric field between two parallel plates is uniform, with magnitude 576 N/C. A proton is held stationary at the positive plate, and an electron is held stationary at the negative plate. The plate separation is 4.30 cm. At the same moment, both particles are released (a) Calculate the distance (in cm) from the positive plate at which the two pass each other. Ignore the electrical attraction between the proton and electron cm (b) Repeat part (a) for a sodium...