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A 5.40 g sample of NH Cl was added to 24.5 mL of 1.19 M NaOH and the resulting solution diluted to 0.100 L. (Assume K-1.01x 1
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as Atomie wit of Molar mass = *= 149, H» lg, Cl = 35.5g, Guian mass of NH4 c. = 5.40 N:140... in of mass es of each alom presMolarity of na V of He used before adolihoin = 0,033 M.1 see Come on vain to V SI = V SR 9.20.1*0,03344 =103-20X5 m 102*10*3

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