A balloon containing methane gas has a volume of 2.30 L at 79.0 °C . What volume will the balloon occupy at 158 °C ?
Answer:
Step 1: Explanation:
We know the ideal gas equation, PV=nRT
where, R=universal gas constant,T=temperature ,P=pressure,V=volume,n=moles.
PV=nRT
or, V/T=K [since nR and Pressure all are assume constant]
So, we have V1/T1 = V2/T2.
Step 2: Extract the data from the question
Given, V1 = 2.30 L and T1= 79 °C = ( 79+273.15 )K = 352.15 K , V2= we need to find and
T2 = 158 °C = ( 158+273.15)K = 431.15 K
Step 3: Calculation
By using above equation
V1/T1 = V2/T2.
or, V2 = V1T2 / T1 = ( 2.30 L × 431.15 K) / 352.15 K= 2.82 L
The new volume is 2.82 L
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