Question

A balloon containing methane gas has a volume of 4.67 L at 65.0 °C. What volume will the balloon occupy at 130 °C? volume: 5.56

Answer 1

We Have

V₁ = 4.67 L

T₁ = 65.0 ⁰C = 65 + 273 = 338 K

T₂ = 130 ⁰C = 130 + 273 = 403 K

V₂ = ?

by using the Charles Law

V₁ /T₁ = V₂ /T₂

Lets put the given values in above formula, we get

V₂ = T₂ $\times$ V₁ /T₁

= 403 K $\times$ 4.67 L / 338 K

= 5.56 L

So the Volume at 130 ⁰C will be 5.56 L