13. At a particular temperature the equilibrium constant for the reaction: H2(g)+F2(g) 2HF(g) is K 100.0....
Equilibrium Concentrations -- A + B = 2C At a particular temperature, K = 1.00×102 for the reaction: H2(g) + F2(g) 2HF(g) In an experiment, at this temperature, 1.00×10-1 mol of H2 and 1.00×10-1 mol of F2 are introduced into a 1.09-L flask and allowed to react. At equilibrium, all species remain in the gas phase. What is the equilibrium concentration (in mol/L) of H2? mol/L 1 pts What is the equilibrium concentration (in mol/L) of HF? mol/L 1 pts...
2. Hydrogen fluoride can be produced from elemental fluorine and hydrogen according to the reaction H2(g) + F2(g) → 2HF(g). The reaction has an equilibrium constant, Kc, of 7.75 x 102 at a certain temperature. a. Calculate the equilibrium concentration of HF(g) if 5.750 mol of H, and Fz are introduced into a 1.500 L flask. b. Calculate the reaction quotient if 3.25 mol of EACH species is introduced into a 3.000 L flask. What does this value tell us...
The equilibrium constant for the reaction below is Kc=115. if the initial concentrations of F2, H2 and HF are all 2.0 M, what are the equilibrium concentrations of H2 and HF? F2(g) + H2(g) <--> 2HF(g)
Assume that the reaction for the formation of gaseous hydrogen fluoride (HF) from hydrogen (H2) and fluorine (F2) has an equilibrium constant K = [HF]2 / [H2][F2] of 1.15×10 2 at a certain temperature. In a particular experiment at this temperature 3.000 mol of each component were added to 1.500 mL flask. Calculate the equilibrium concentration of all species using an ICE table. Let x equal the number of moles per litre of H2 consumed to reach equilibrium.
12. The equilibrium constant for the reaction of fluorine gas with bromine gas at 300 K is 54.7 and the reaction is: Br2(g) +F2(g) 2 BrF(g) What is the equilibrium concentration of fluorine if the initial concentrations of bromine and fluorine were 0.125 moles/liter in a sealed container and no product was present initially? Submit Answer Tries 0/99
3. Consider the following reaction: 2HF(g) = H2(g) + F2(g) Initially a container is filled with pure HF(g) at a pressure of 2 atm, after which equilibrium is reached. If y is the partial pressure of H2 at equilibrium, a) Express the value of Kp using y.
The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K: H2(g) + I2(g) ---------->2HI(g) 1) Calculate the equilibrium concentrations of reactants and product when 0.309 moles of H2 and 0.309 moles of I2 are introduced into a 1.00 L vessel at 698 K. [H2] = M? [I2] = M? [HI] = M? 2.The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K: PCl5(g)------->PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a...
Consider the following reaction: 2HF(g) H2(g) + F2(g) Initially a container is filled with pure HF(g) at a pressure of 2 atm, after which equilibrium is reached. If y is the partial pressure of H2 at equilibrium, Express the value of Kp using y. a) b) If K = 0.01 at this temperature, calculate the equilibrium concentrations of the 3 species.
Hydrogen and fluorine react to form hydrogen fluoride, like this: H2(9)+F2(9) 2 HF(G) The reaction is exothermic. Suppose a mixture of H2, F, and HF has come to equilibrium in a closed reaction vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left. perturbation change in composition shift in equilibrium to the right The temperature is...
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.329 M HI, 4.41×10-2 M H2 and 4.41×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.54×10-2 mol of H2(g) is added to the flask? [HI] = M [H2] = M [I2] = M