Question

Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Standard Gibbs free energy of formation values
Thermodynamic Properties at 298 K Organic Compounds AG kJ/mol /(mol-K) дне kJ/mol Substance Name Formula дне kJ/mol Ag(s) Ag
82.4 2,2-Dimethylpentane 3,3-Dimethylpentane 2,3-Dimethylpentane 2,4-Dimethylpentane 2-Methylheptane 2,2-Dimethylhexane |2,3-
263.8 -166.2 -127.6 CH3CHO(9) CH3CO2H(I) 159.8 -389.9 -484.3 160.7 -174.8 CHaCH-оH() CH3CN(I) CHCI3(g) CHCI3(1) -277.6 149.6
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Answer #1

6Cl2(g) + 2Fe2O3(s) -------------> 4FeCl3(s) + 3O2(g)

\DeltaG0rxn = \Delta G0f products - \Delta G0f reactants

                = 3*0 + 4*-344 -(6*0 + 2*-742.2)

               = 108.4KJ/mole >>>>answer

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