Homework Answers
Ti = 35.0 oC
Tf = 100.0 oC
here
Cl = 4.184 J/goC
Heat required to convert liquid from 35.0 oC to 100.0 oC
Q1 = m*Cl*(Tf-Ti)
= 11.3 g * 4.184 J/goC *(100-35) oC
= 3073.148 J
Lv = 2260.0 J/g
Heat required to convert liquid to gas at 100.0 oC
Q2 = m*Lv
= 11.3g *2260.0 J/g
= 25538 J
Total heat required = Q1 + Q2
= 3073.148 J + 25538 J
= 28611 J
= 28.6 KJ
Answer: 28.6 KJ
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