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Calculate the amount of heat that must be absorbed by 100.0 g of water at 20.0°C...

Calculate the amount of heat that must be absorbed by 100.0 g of water at 20.0°C to convert it to steam (water vapor) at 110.0°C. Given:
Specific heats:   (liq) = 4.18 J/g·°C    (steam) = 1.84 J/g·°C                         DHvap = 40.7 kJ/mol

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