Question

A simple pendulum with mass m = 1.7 kg and length L = 2.47 m hangs from the ceiling. It is pulled back to an small angle of = 11.8° from the vertical and released at t = 0. 1) What is the period of oscillation? s Submit Help You currently have 10 submissions for this question. Only 15 submission are allowed. You can make 5 more submissions for this question. Your sih missions: Computed value: 2.9 Submitted: Thursday, November 21 at 5:59 PM Feedback: 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? N Submit Help 3) What is the maximum speed of the pendulum? m/s Submit Help 4) What is the angular displacement at t = 3.47 s? (give the answer as a negative angle if the angle is to the left of the vertical) Submit Help 5) What is the magnitude of the tangential acceleration as the pendulum passes through the equilibrium position? m/s2 Submit 6) What is the magnitude of the radial acceleration as the pendulum passes through the equilibrium position? m/s2 Submit

Answer 1

L=2+47m m=1.7kg Initial 0o=11.80 = 0.208rad mean position my coso

Criven that length=2.47m mass = 1.7kg angle from vertical = 11.8° = 11.8XA = 0.206 bal IS @ Time period to enjoy = an 2.47 - 3.15 Jee. Time Per on 2.47 - 3.15 see. 9 9.8 The magnitude of the force on the Pendulum perpendicular to the string (too) f = mo = 9.7x9.8 x 0.206 ² 3.43N

- - The speed of the Pendulum V=WL & wodo? 6².2 for max. speed io=0 Vmax : WoooL = g. OoL = JgLO. = 19.8 x 2.97 × 0.206 {"max = 1.014 m/see.] @ Angular dis placement 0 = Oo sin (Wot - A ) 0 - 0. sin(JE5-/2) 0.4 0.206 sin [ 19:143:47 - 17 - 0:206.4 (5:39) 10= 0.0192 rad ® Tangential Acceleration- a=42=- w²0L for equilibrium position 0=0 , [a=0] • t = 3.47se - • .

you also find Radial Acceleration - a = W²L a wo?[0²-0²] for equilibrium o=0 ac = wo?:0² L = 9.0?1L qca Vmax (1.0142 13 19 = 0 g - 10.206)²x 9,8 = 0.4158 m/see.