Question

Given data:       Weight of female nurses in a hospital in lbs. 110     98       119     105     99     &nbs

  1. Given data:       Weight of female nurses in a hospital in lbs.

110     98       119     105     99       100     100     110

Compute the ff. using ungrouped data

  1. Mean
  2. Median
  3. Mode
  4. Variance
  5. Standard deviation

     V. The following data represent the respective heights (in inches) of 30 students enrolled in a physical education class. Construct a frequency distribution with eight class intervals.

60.0              59.7                        70.1                        58.2                         62.1   

60.1             62.3                        62.4                        68.3                          63.3    

67.3              62.7                        58.0                        67.3                               72.8

64.4              67.1                        66.4                        61.7                               69.4

65.3              65.7                        66.3                        68.1                               68.3

65.4              66.7                        61.4                        64.1                               69.2

  1. Solve the ff. using grouped data:
  1. Mean
  2. Median
  3. Mode
  4. Variance
  5. Standard Deviation
  1. Draw bar graph
  1. Here's the data for the 20 individuals all male where height is measured in inches. Self esteem is measured based on the average of 10 1-to-5 rating items where higher scores mean higher self esteem. Compute correlation coefficient.

Person

Height

Self Esteem

1

68

4.1

2

71

4.6

3

62

3.8

4

75

4.4

5

58

3.2

6

60

3.1

7

67

3.8

8

68

4.1

9

71

4.3

10

69

3.7

11

68

3.5

12

67

3.2

13

63

3.7

14

62

3.3

15

60

3.4

16

63

4.0

17

65

4.1

18

67

3.8

19

63

3.4

20

61

3.6

0 0
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Answer #1

1. Here we have to compute s

ummary statistics i.e. mean, median, mode, variance, standard deviation.

For mean we have,mu =Sum(Xi)/N where Xi is observations and N is total no of observations.

So we have, mu= (110+98+119+105+99+100+100+110)/8 =92.625=mean.

For mode, we know that it is the value that occurs max no of time in data, hence mode is 100

Median is the value which occurs in the middle of the list of values given hence, on rearranging the values we get, 98,99,100,100,105,110,110,119. We can see that 100 is the middle most value hence it is the median of given data.

6M 사, ba.구 sx50-Y mv 236 4 183 S& 6 ad 63 6 3 70 12 402 3 34 28 24 73 30 6 8 73 30 3 0 Medans. Mode > We can see tnat clars: 66-68 tou masu munn frequ Atent// rnode hiner, mode is 63 S$ 60 62 6牛 6668707s 14 629 6.&I 2 5041 al 3266 23S4 33 244 14.44 9 36 10 4 9-6 14.44 16 R +--5625- マ 3 3 69 63600 4 929 186 234.6 30s 3 38 233 に41 04) 6I 464 24989 3144 36 00 13.69 1a.as b 34 3 69 又14,4. 20914 ir 文bbig 63969 16.8 4.44 4025 24461 3461 40 372] S9.6 219. 219.6 2-94 Sum 4933.4 um85912 errelatm 20 246.88-245 577 130367313 4 0. 41S3 7R 163? 4.29

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