Question

i) Determine the single capacitor that is equivalent to the parallel combination of capacitors shown in the figure. (5 points) 3.00 μF 6.00 μF i) What is the total charge contained in the configuration? (5 points) 12.0 uF 24.0 AF 18.0 V i) What is the capacitance of a parallel plate capacitor with metal plates, each of area 1.00 m2, separated by 1.00 mm? (5 points) ii) What charge is stored in this capacitor if a voltage of 3.00x103 V is applied to it? (5 points)

Answer 1

A)

i)

equivalent capacitance

C=3+6+12+24

C=45 uF

ii)

Total charge

Q=CV =45*18

Q=810 uC

or

Q=8.1*10^-4 C (1 uC =10^-6 C)

B)

i)

Capacitance is given by

C=e_oA/d =(8.8542*10^-12)(1)/(1*10^-3)

C=8.8542*10^-9 F or 8.8542 uF

ii)

Charge stored in capacitor is

Q=CV =(8.8542*10^-9)(3*10³)

Q=2.65626*10^-5 C or 26.5626 uC